TypeError: ‘function’ 类型的参数不可迭代
TypeError: argument of type ‘function’ is not iterable
Python “TypeError: argument of type ‘function’ is not iterable”发生在我们对函数使用in
ornot in
运算符但忘记调用它时。要解决错误,请确保调用该函数,例如my_func()
。
下面是错误如何发生的示例。
def get_list(): return ['a', 'b', 'c'] # ⛔️ TypeError: argument of type 'function' is not iterable print('a' in get_list) # 👈️ forgot to call function
get_list()
,所以我们的代码试图检查函数中的成员而不是列表中的成员。要解决错误,请确保调用该函数。
def get_list(): return ['a', 'b', 'c'] print('a' in get_list()) # 👉️ True print('a' not in get_list()) # 👉️ False
We used parentheses to invoke the function, so now we check for membership in
the list rather than the function.
The
in operator
tests for membership. For example, x in s
evaluates to True
if x
is a
member of s
, otherwise it evaluates to False
.
my_str = 'hello world' print('world' in my_str) # 👉️ True print('another' in my_str) # 👉️ False
x
not in s
returns the negation of x
in s
.
All built-in sequences and set types support the in
and not in
operators.
When used with a dictionary, the operators check for the existence of the
specified key in the dict
object.
Conclusion #
Python “TypeError: argument of type ‘function’ is not iterable”发生在我们对函数使用in
ornot in
运算符但忘记调用它时。要解决错误,请确保调用该函数,例如my_func()
。